Gate EC-2012 Question Paper With Solutions

Q. 38 A binary symmetric channel (BSC) has a transition probability of 1/8. If the binary symbol X is such that P(X = 0) = 9/10, then the probability of error for an optimum receiver will be

(A) 7/80

(B) 63/80

(C) 9/10

(D) 1/10

Answer:

Explanation:

Not Required

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