__Copper Square Angle Weight Calculator:__

__Copper Square Angle Weight Calculator:__

Enter the vales of width, W_{(cm)}, thickness of the tube, T_{(cm)} and Length, L_{(cm)} to determine the value of Weight, W_{(g)}.

__Copper Square Angle Weight Formula: __

__Copper Square Angle Weight Formula:__

A Copper Square Angle is a structural component made from copper with a square cross-section and an L-shape. It is designed to provide strength and durability in various applications. The physics of its weight calculation involves understanding how the material’s density and the geometric properties of the angle impact its overall mass.

The weight of a Copper Square Angle is determined by calculating the volume of copper it contains and then multiplying this volume by the density of copper.

The density of copper reflects its mass per unit volume, which, combined with the volume of copper in the angle, yields the total weight.

The hollow section formed by the L-shape reduces the material used, making the component lighter and more cost-effective without significantly compromising strength.

Weight, W_{(g)} in grams equals the difference between the square of width, W_{(cm)} in centimetres and the square of the difference between width, W_{(cm)} and thickness of the tube, T_{(cm)} in centimetres then divided by 2 and multiplied by Length, L_{(cm)} in centimetres and density of the copper material, d_{(g/cm3)} in grams per cubic centimetre.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

W_{(g)} = weight in grams, g.

W_{(cm)} = width in centimetres, cm.

T_{(cm)} = thickness in centimetres, cm.

L_{(cm)} = length in centimetres, cm.

d_{(g/cm3)} = density in grams per cubic centimetres, g/cm^{3}.

__Copper Square Angle Weight Calculation:__

1. A Copper Square Angle has a width of 4 cm, a thickness of 0.5 cm, a length of 100 cm, and the density of copper is 8.96 g/cm^{3}. Calculate the weight of the angle.

Given: W_{(cm)} = 4cm, T_{(cm)} = 0.5cm, L_{(cm)} = 100cm, d_{(g/cm3)} = 8.96g/cm^{3}.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

W_{(g)} = ([4^{2} – (4 – 0.5)^{2}] / 2 ) * 100 * 8.96

W_{(g)} = (3.75 / 2) * 100 * 8.96

W_{(g)} = 1.875 * 100 * 8.96

W_{(g)} = 1680g.

2. A Copper Square Angle has a width of 6 cm, a thickness of 1 cm, and a material density of 8.96 g/cm^{3}. If the angle weighs 2150 g, calculate the length of the angle.

Given: W_{(cm)} = 6cm, T_{(cm)} = 1cm, W_{(g)} = 2150g, d_{(g/cm3)} = 8.96g/cm^{3}.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

L_{(cm)} = W_{(g)} / ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * d_{(g/cm3)}

L_{(cm)} = 2150 / ([6^{2 }– (6 – 1)^{2}]) * 8.96

L_{(cm)} = 2150 / 16.65 * 8.96

L_{(cm)} = 43.63cm.