Q. 46 What will be the output of the following pseudo-code when parameters are passed by reference and dynamic scoping is assumed?
a=3;
void n(x) {x = x * a; print(x);}
void m(y) {a = 1; a = y - a; n(a); print(a);}
void main() {m(a);}
(A) 6, 2
(B) 6, 6
(C) 4, 2
(D) 4, 4
Answer: (D)
Explanation:
