Gate CS-2012 Question Paper With Solutions

Q. 35 Suppose a circular queue of capacity ^n – 1h elements is implemented with an
array of n elements. Assume that the insertion and deletion operations are carried
out using REAR and FRONT as array index variables, respectively. Initially,
REAR = RFONT = 0. The conditions to detect queue full and queue empty are

(A) full: (REAR+1)mod n == FRONT
empty: REAR == FRONT

(B) full: (REAR+1)mod n == FRONT
empty: (FRONT+1) mod n == REAR

(C) full: REAR == FRONT
empty: (REAR+1) mod n == FRONT

(D) full: (FRONT+1) mod n == REAR
empty: REAR == FRONT

Answer: (A)

Explanation:

Gate CS-2012 Question Paper With Solutions

Gate CS-2012 Question Paper With Solutions Gate CS-2012 Question Paper With Solutions

Learn More:   Gate ME 2015-1 Question Paper With Solutions

LEAVE A REPLY

Please enter your comment!
Please enter your name here