__Gravitational Torque Calculator:__

__Gravitational Torque Calculator:__

Enter the values of mass of the object, m_{(kg)}, acceleration due to gravity, g(m/s^{2}) and radius, r_{(m)} to determine the value of gravitational torque, T_{g(N.m)}.

__Gravitational Torque Formula:__

__Gravitational Torque Formula:__

Gravitational torque is a measure of the rotational effect caused by gravity on an object that is not centered on its axis of rotation.

Gravitational torque, T_{g(N.m)} in Newton metres is calculated by the product of mass of the object, m_{(kg)} in kilograms, acceleration due to gravity, g(m/s^{2}) in metre per second squared and radius, r_{(m)} in metre.

Gravitational torque, T_{g(N.m) }= m_{(kg)} * g_{(m/s2)} * r_{(m)}

T_{g(N.m) }= gravitational torque in Newton metres, N.m.

m_{(kg) }= mass of the object in kilograms, kg.

g_{(m/s2)} = acceleration due to gravity in metre per second squared, m/s^{2}. (approximately 9.81m/s^{2} on the surface of the Earth).

r_{(m) }= radius in metre, m.

__Gravitational torque Calculation:__

- Consider a playground seesaw with a child sitting 2 metres from the pivot point. If the child has a mass of 30kg, calculate the gravitational torque exerted by the child on the seesaw.

Given: m_{(kg) }= 30kg, g_{(m/s2)} = 9.81m/s^{2}, r_{(m) }= 2m.

Gravitational torque, T_{g(N.m) }= m_{(kg)} * g(m/s^{2}) * r_{(m)}

T_{g(N.m) }= 30 * 9.81 * 2

T_{g(N.m) }= 588.6N.m

- A sign is mounted on a pole, where the center of mass of the sign is 0.5 metres from the pole. If the acquired gravitational torque on the pole is 73.575N.m. Determine the mass.

Given: T_{g(N.m) }= 73.575N.m, g_{(m/s2)} = 9.81m/s^{2}, r_{(m) }= 0.5m.

Gravitational torque, T_{g(N.m) }= m_{(kg)} * g_{(m/s2)} * r_{(m)}

m_{(kg)} = T_{g(N.m)} / g_{(m/s2)} * r_{(m)}

m_{(kg)} = 73.575 / 9.81 * 0.5

m_{(kg)} = 15kg.