__Aluminium Round Bar Weight Calculator:__

__Aluminium Round Bar Weight Calculator:__

Enter the values of square of diameter of the bar, D_{(cm)}, and length of the bar, L_{(cm)} to determine the value of aluminium round bar weight, W_{(g)}.

__Aluminium Round Bar Weight Formula:__

__Aluminium Round Bar Weight Formula:__

An aluminium round bar is a cylindrical piece of aluminium, commonly used in construction, manufacturing, and various engineering applications.

The aluminium round bar, being cylindrical in shape, is characterized by its diameter, length, and material density. The weight of the bar is directly proportional to its volume, which is a product of its cross-sectional area and length, and the density of aluminium.

The density of aluminium, which is typically around 2.7 grams per cubic centimetre, indicates how much mass is contained within a unit volume. As the dimensions of the bar increase, the volume increases, leading to a corresponding increase in weight.

Aluminium round bar weight, W_{(g)} in grams is calculated by dividing the product of square of diameter of the bar, D_{(cm)} in centimetres, length of the bar, L_{(cm)} in centimetres, density of acrylic bar, d_{(g/cm3)} in grams per cubic centimetre and pi by 4.

Aluminium round bar weight, W_{(g)} = 3.14 * D^{2}_{(cm)} * L_{(cm)} * d_{(g/cm3)} / 4

W_{(g)} = aluminium round bar weight in grams, g.

D_{(cm)} = diameter of the bar in centimetres, cm.

L_{(cm)} = length of the bar in centimetres, cm.

d_{(g/cm3)} = density of acrylic bar in grams per cubic centimetre, g/cm^{3}.

__Aluminium Round Bar Weight Calculation:__

__Aluminium Round Bar Weight Calculation:__

**1.**An aluminium round bar has a diameter of 4 cm, a length of 100 cm, and the density of aluminium is 2.7 g/cm^{3}. Calculate the weight of the bar.

Given: D_{(cm)} = 4cm, L_{(cm)} = 100cm, d_{(g/cm3)} = 2.7g/cm^{3}.

Acrylic round bar weight, W_{(g)} = 3.14 * D^{2}_{(cm)} * L_{(cm)} * d_{(g/cm3)} / 4

W_{(g)} = 3.14 * 4^{2} * 100 * 2.7 / 4

W_{(g)} = 3.14 * 1600 * 2.7 / 4

W_{(g)} = 3391.2g.

- An aluminium round bar weighs 5000 g, has a diameter of 4 cm, and the density of aluminium is 2.7 g/cm
^{3}. Find the length of the bar.

Given: W_{(g)} =5000g, D_{(cm)} = 4cm, d_{(g/cm3)} = 2.7g/cm^{3}.

Acrylic round bar weight, W_{(g)} = 3.14 * D^{2}_{(cm)} * L_{(cm)} * d_{(g/cm3)} / 4

L_{(cm)} = W_{(g)} * 4 / 3.14 * D^{2}_{(cm)} * d_{(g/cm3)}

L_{(cm)} = 5000 * 4 / 3.14 * 4^{2} * 2.7

L_{(cm)} = 147.31cm.