__Acetal Round Bar Weight Calculator:__

__Acetal Round Bar Weight Calculator:__

Enter the values of square of diameter of the bar, D_{(cm)}, and length of the bar, L_{(cm)} to determine the value of acetal round bar weight, W_{(g)}.

__Acetal Round Bar Weight Formula:__

__Acetal Round Bar Weight Formula:__

An Acetal round bar is a cylindrical rod made from Acetal, a thermoplastic polymer known for its high strength, low friction, and excellent dimensional stability.

Acetal, also known as Polyoxymethylene (POM), is widely used in precision engineering applications due to its excellent mechanical properties, such as high tensile strength, fatigue resistance, and low moisture absorption.

The round bar shape offers a uniform cross-section, making it ideal for machining into various components like gears, bushings, and bearings.

Acetal is characterized by a low coefficient of friction, which reduces the wear and tear on moving parts, and its resistance to moisture, chemicals, and solvents enhances its durability in various environments.

The round bar’s shape offers a uniform cross-section, making it straightforward to machine into components with tight toleranc

Acetal round bar weight, W_{(g)} in grams is calculated by dividing the product of square of diameter of the bar, D_{(cm)} in centimetres, length of the bar, L_{(cm)} in centimetres, density of acetal bar, d_{(g/cm3)} in grams per cubic centimetre and pi by 4.

Acetal round bar weight, W_{(g)} = 3.14 * D^{2}_{(cm)} * L_{(cm)} * d_{(g/cm3)} / 4

W_{(g)} = acetal round bar weight in grams, g.

D_{(cm)} = diameter of the bar in centimetres, cm.

L_{(cm)} = length of the bar in centimetres, cm.

d_{(g/cm3)} = density of acetal bar in grams per cubic centimetre, g/cm^{3}.

__Acetal Round Bar Weight:__

__Acetal Round Bar Weight:__

- An Acetal round bar has a diameter of 4 cm, length of 100 cm, and the density of Acetal is 1.41 g/cm
^{3}. Calculate the weight of the bar.

Given: D_{(cm)} = 4cm, L_{(cm)} = 100cm, d_{(g/cm3)} = 1.41g/cm^{3}.

Acetal round bar weight, W_{(g)} = 3.14 * D^{2}_{(cm)} * L_{(cm)} * d_{(g/cm3)} / 4

W_{(g)} = 3.14 * 4^{2} * 100 * 1.41 /4

W_{(g)} = 3.14 * 4 * 100 * 1.41

W_{(g)} = 1770.95g.

- An Acetal round bar has a diameter of 3 cm, weighs 1,000 grams, and the material density is 1.41 g/cm
^{3}. Find the length of the bar.

Given: D_{(cm)} = 3cm, W_{(g)} = 1000g, d_{(g/cm3)} = 1.41g/cm^{3}.

Acetal round bar weight, W_{(g)} = 3.14 * D^{2}_{(cm)} * L_{(cm)} * d_{(g/cm3)} / 4

L_{(cm)} = W_{(g)} * 4 / 3.14 * D^{2}_{(cm)} * d_{(g/cm3)}

L_{(cm)} = 1000 * 4 / 3.14 * 3^{2} * 1.41

L_{(cm)} = 100.5cm.