__Support Force Calculator:__

__Support Force Calculator:__

Enter the values of masses of the objects, M_{1(kg)} and M_{2(kg)} and acceleration due to gravity, a_{(m/s2)} to determine the value of support force, SF_{(N)}.

__Support Force Formula:__

__Support Force Formula:__

Support force refers to the force that a support structure must exert to hold up objects against the force of gravity.

Support force, SF_{(N)} in Newtons is equated by the product of sum of masses of the objects, M_{1(kg)} and M_{2(kg)} in kilograms and acceleration due to gravity, a_{(m/s2)} in metres per second squared.

Support force, SF_{(N)} = (M_{1(kg)} + M_{2(kg)}) * a_{(m/s2)}

SF_{(N)} = support force in Newtons, N.

M_{1(kg)} + M_{2(kg)} = masses of the objects in kilograms, kg.

a_{(m/s2)} _{ }= acceleration due to gravity in metres per second squared, m/s^{2}, approximately 9.81m/s^{2} on the surface of the Earth.

__Support Force Calculation:__

__Support Force Calculation:__- Calculate the support force required to hold up two objects with masses of 10 kg and 15 kg, respectively.

Given: M_{1(kg)} = 10kg, M_{2(kg)} = 15kg.

Support force, SF_{(N)} = (M_{1(kg)} + M_{2(kg)}) * a_{(m/s2)}

SF_{(N)} = ( 10 + 15 ) * 9.81

SF_{(N)} = 245.25N.

- Assume you have a support force of 196.2 Newtons, the mass of the second object is 10 kg, and the acceleration due to gravity is 9.81m/s
^{2}. Find M_{1(kg)}.

Given: SF_{(N)} = 196.2N, M_{2(kg)} = 10kg.

Support force, SF_{(N)} = (M_{1(kg)} + M_{2(kg)}) * a_{(m/s2)}

M_{1(kg)} = ( SF_{(N)} / a_{(m/s2)} ) – M_{2(kg)}

M_{1(kg)} = (196.2 / 9.81) – 10

M_{1(kg)} = 20 – 10

M_{1(kg)} = 10kg.

__How to Calculate Support Reactions of a Simply Supported Beam with a Point Load:__

__How to Calculate Support Reactions of a Simply Supported Beam with a Point Load:__