__Maximum Velocity Calculator:__

__Maximum Velocity Calculator:__

Enter the values of Mass of the object m_{(kg)}, Total Accelaration, Density of the fluid a_{(m/s}^{2}_{)}, Cross-sectional Area A_{(m}^{2}_{)} & Coefficient of drag C to determine the value of Maximum Velocity Vmax_{(m/s).}

__Maximum Velocity Formula:__

__Maximum Velocity Formula:__

The Maximum Velocity Vmax_{(m/s)} in meter per second is equal to the SQRT of the value of 2 into multiply the Mass of the object m_{(kg)} in kilogram and again multiply the Total Accelaration a_{(m/s}^{2}_{)} in meter per second square to divided by the Density of the fluid p_{(kg/m}^{3}_{)} in kilogram per meter cube and multiply the Cross-sectional Area A_{(m}^{2}_{)} in meter square and again multiply the Coefficient of drag ( C ).

The Formula of Maximum Velocity can be writtern as,

Vmax_{(m/s)} = SQRT ( 2 * m_{(kg)} * a_{(m/s}^{2}_{)} / ( p_{(kg/m}^{3}_{)} * A_{(m}^{2}_{)} * C ) )

Here,

Vmax_{(m/s)} = Maximum Velocity in meter per second

m_{(kg)} = Mass of the object in kilogram

a_{(m/s}^{2}_{)} = Total Accelaration in meter per second square

p_{(kg/m}^{3}_{)} = Density of the fluid in kilogram per meter cube

A_{(m}^{2}_{)} = Cross-sectional Area in meter square

C = Coefficient of drag

__Calculation for Maximum Velocity:__

__Calculation for Maximum Velocity:__

1)Determine the Maximum Velocity and given for Mass of the object = 15kg , Accelaration = 20m/s^{2} , Density = 1.1kg/m^{3} , Cross-sectional Area = 2m^{2} , Coefficient of drag = .45.

Answer

Vmax = √ ( 2 * m * a / ( p * A * C ) )

Vmax = √ ( 2 * 15 * 20 / ( 1.1 * 2 * .45 ) )

Vmax = 24.61m/s.

2)Determine the Cross-sectional Area and given for Mass of the object = 15kg , Accelaration = 20m/s^{2} , Density = 1.1kg/m^{3} , Coefficient of drag = .45 , Maximum Velocity = 24.61.

Answer

Vmax = √ ( 2 * m * a / ( p * A * C ) )

24.61 = √ ( 2 * 15 * 20 / ( 1.1 * A * .45 ) )

A = 2m^{2}.

__Find maximum velocity:__

__Find maximum velocity:__