Magnetic Force Between Current-Carrying Wires Calculator:
Magnetic force between current carrying wires calculator will get the magnitude of the magnetic force that appears when current flows through two wires that are close to each other.
Within a few paragraphs, you will learn why this phenomenon occurs and how to calculate the magnitude of the magnetic force.
How can you quickly determine whether the force between the wires is attractive or repulsive?
When current flows through a straight wire, an induced magnetic field appears, and its direction can be found using the right-hand rule. We also know that when a charge moves through a magnetic field, it experiences a force called the Lorentz force.
Suppose we have a current-carrying wire that induces a magnetic field, then we place another current-carrying wire so that it is affected by this induced magnetic field. Charges moving inside the second wire will experience a force, which will cause the cables to move closer or further apart used to find the magnetic force between two parallel wires.
Magnetic Force Between Wires Equation:
Magnetic force between wires F/L(N) in Newton is equal to the permeability of free space that has a constant value μ0(m/A) in Meter per Ampere and multiply the current flowing in the first wire Ia(A) in Ampere and multiply the current flowing in the second wire Ib(A) in Ampere and divided by the two pi 2π and multiply the distance d(m) in meter.Hence the magnetic force between wires equation can be written as
F/L(N) =μ0(m/A) *Ia(A)*Ib(A) /(2π*d(m))
Ia,Ib are the current flowing in the first and second wires in Ampere
D=is the distance between the wires in meter
F/L=is the force per unit length acting on each wire in Newton
μ0 =is the permeability of free space that has a constant value μ=4π *10-7Tm/A
Example:1
IF 10 A of current flows in the first wire, 6A of current flows in the second wire.The distance between two wires is 9 m and find the magnetic force between two wires?
Answer:
Given that
Current in the first wire la =10A
Current in the second wire lb =6A
Distance between two wires d=9m
F/L =μ *Ia*Ib /(2π*d)
F/L= 4* π *10-7*10 / (2* π *9)
F=0.0000013333N
Therefore the magnetic field F=0.0000013333N
Example:2
IF 28 A of current flows in the first wire, 32A of current flows in the second wire.The distance between two wires is 25 m and find the magnetic force between two wires?
Answer:
Given that
Current in the first wire la =28A
Current in the second wire lb =32A
Distance between two wires d =25m
F/L =μ *Ia*Ib /(2π*d)
F/L= 4* π *10-7*28 / (2* π *25)
F=0.000007168N
Therefore the magnetic force (F) =0.000007168N
Very informative, thank you so much