**Imbalace Force Calculator**

Enter the values of mass, m_{(kg)}, radius, R_{(m)} and frequency, f_{(Hz)} to determine the value of Imbalance force, IF_{(N)}.

**Imbalace Force Formula**

Imbalance force is calculated to determine the force exerted due to mass imbalance in rotating systems. This force is especially relevant in engineering contexts where rotating parts may have uneven mass distribution, leading to vibrations and additional stresses.

Imbalance force, IF_{(N)} in Newtons is calculated by the product of mass, m_{(kg)} in kilograms, radius, R_{(m)} in metres and square of 6.28 and frequency, f_{(Hz)} in Hertz.

Imbalance force, IF_{(N)} = m_{(kg)} * R_{(m)} * ( 6.28 * f_{(Hz)} )^{2}

IF_{(N)} = imbalance force in Newtons, N.

m_{(kg)} = mass in kilograms, kg.

R_{(m)} = radius in metres, m.

f_{(Hz)} = frequency in Hertz, Hz.

__Imbalace Force Calculation:__

- Suppose a flywheel in a car engine has a mass of 5 kg with an imbalanced mass located 0.04 metres from the rotation axis. If the engine runs at 33.33Hz, calculate the imbalance force exerted.

Given: m_{(kg)} = 5kg, R_{(m)} = 0.04m, f_{(Hz)} = 33.33Hz.

Imbalance force, IF_{(N)} = m_{(kg)} * R_{(m)} * ( 6.28 * f_{(Hz)} )^{2}

IF_{(N)} = 5 * 0.04 * ( 6.28 * 33.33 )^{2}

IF_{(N)} = 5 * 0.04 * 43879.47

IF_{(N)} = 8775.89N.

- A machine component is rotating with an imbalance due to a mass of 0.5 kg positioned eccentrically. The rotational frequency of 5Hz and this setup results in an imbalance force of 200 Newtons. Calculate the radius in metres.

Given: m_{(kg)} = 0.5kg, IF_{(N)} = 200N, f_{(Hz)} = 5Hz.

Imbalance force, IF_{(N)} = m_{(kg)} * R_{(m)} * ( 6.28 * f_{(Hz)} )^{2}

R_{(m)} = IF_{(N)} / m_{(kg)} * ( 6.28 * f_{(Hz)} )^{2}

R_{(m)} = 200 / 0.5 * ( 6.28 * 5)^{2}

R_{(m)} = 200 / 1973.920885

R_{(m)} = 0.1013m.