## Hoist Motor Power Calculator

Enter the values of mass, m_{(kg)}, lifting speed, V_{(m/s)} and motor efficiency, N to determine the value of Hoist motor power, HMP_{(W)}.

__Hoist Motor Power Formula:__

__Hoist Motor Power Formula:__

Hoist motor power signifies the electrical power a hoist motor needs to generate in order to lift a specific weight.

The weight of the object being lifted, typically expressed in kilograms (kg). A heavier object naturally requires more power to lift. This constant acceleration due to gravity (approximately 9.81 m/s²) acts on the mass, influencing the lifting force needed.

The desired speed at which the object needs to be lifted, measured in meters per second (m/s). A faster lifting speed translates to a higher power demand. No motor is perfect. This value, ranging from 0 to 1 (typically 0.7-0.9), accounts for power losses within the motor due to friction and heat generation.

Hoist motor power plays a vital role in selecting the right hoist for a specific job. Furthermore, considering motor efficiency helps optimize power consumption and minimize energy waste.

Hoist motor power, HMP_{(W)} in watts is calculated by multiplying the mass, m_{(kg)} of the object being lifted in kilograms by the acceleration due to gravity, g_{(m/s2)} approximately 9.81 m/s^{2} in metres per second squared by the lifting speed, V_{(m/s)} in metres per second and then dividing by the motor efficiency, N.

Hoist motor power, HMP_{(W)} = m_{(kg)} * g_{(m/s2)} * V_{(m/s)} / N

HMP_{(W)} = hoist motor power in watts, W.

m_{(kg)} = mass in kilograms, kg.

g_{(m/s2)} = acceleration due to gravity in metres per second squared, m/s^{2}.

V_{(m/s)} = lifting speed in metres per second, m/s.

N = motor efficiency.

__Hoist Motor Power Calculation:__

__Hoist Motor Power Calculation:__

- A hoist needs to lift a 200 kg object at a speed of 1 meter per second (m/s). The motor efficiency is 80% (N = 0.8). What is the required hoist motor power?

Given: m_{(kg)} = 200 kg, g_{(m/s2)} = 9.81 m/s^{2}, V_{(m/s)} = 1 m/s, N = 0.8

Hoist motor power, HMP_{(W)} = m_{(kg)} * g_{(m/s2)} * V_{(m/s)} / N

HMP_{(W)} = 200 * 9.81 * 1 / 0.8

HMP_{(W)} = 2452.5 W

- A hoist motor has a power output of 1500 watts (W) and an efficiency of 75% (N = 0.75). It needs to lift a 100 kg object. What lifting speed (V) can be achieved?

Given: HMP = 1500 W, m = 100 kg, g = 9.81 m/s², N = 0.75

Hoist motor power, HMP_{(W)} = m_{(kg)} * g_{(m/s2)} * V_{(m/s)} / N

V_{(m/s)} = HMP_{(W)} * N / m_{(kg)} * g_{(m/s2)}

V_{(m/s)} = 1500 * 0.75 / (100 * 9.81

V_{(m/s)} = 1.53m/s.