__Drop Force Calculator:__>

__Drop Force Calculator:__>

Enter the values of initial momentum, M_{i(kg.m/s)}, final momentum, M_{f(kg.m/s)} and time, t_{(s)} to generate the value of Drop Force, F_{d(N)}.

__Drop Force Formula:__

__Drop Force Formula:__

Drop force refers to the force exerted over time to change an object’s momentum, typically from a higher to a lower value, effectively measuring the rate of this momentum change.

Drop force, F_{d(N)} in Newtons is equal to the change in momentum, which is the difference between the initial momentum, M_{i(kg.m/s)} in kilogram metre per second and the final momentum, M_{f(kg.m/s)} in kilogram metre per second divided by the time interval, t_{(s)} in seconds over which the change occurs.

Drop force, F_{d(N)} = (M_{i(kg.m/s) }– M_{f(kg.m/s)}) / t_{(s)}

F_{d(N)} = drop force in Newtons, N.

M_{i(kg.m/s)} = initial momentum in kilogram metre per second, kg.m/s.

M_{f(kg.m/s) }= final momentum in kilogram metre per second, kg.m/s.

t_{(s)} = time in seconds, s.

__Drop Force Calculation:__

__Drop Force Calculation:__

**A car of mass 1000 kg decelerates from 20 m/s to 0 m/s in 5 seconds. Calculate the drop force exerted by the car.**

**Given: **M_{i(kg.m/s)} = 1000kg * 20 = 20000kg.m/s, M_{f(kg.m/s) }= 0kg.m/s, t_{(s)} = 5s.

Drop force, F_{d(N)} = (M_{i(kg.m/s) }– M_{f(kg.m/s)}) / t_{(s)}

F_{d(N)} = (20000 – 0) / 5

F_{d(N)} = 4000N.

- Suppose a hockey puck with an initial momentum of 30 kg·m/s comes to a final momentum of 10 kg·m/s. If the drop force exerted during this process is 5 N, find the time over which this change occurs.

**Given: **M_{i(kg.m/s)} = 30kg.m/s, M_{f(kg.m/s) }= 10kg.m/s, F_{d(N)} = 5N.

Drop force, F_{d(N)} = (M_{i(kg.m/s) }– M_{f(kg.m/s)}) / t_{(s)}

t_{(s)} = (M_{i(kg.m/s) }– M_{f(kg.m/s)}) / F_{d(N)}

t_{(s)} = (30 – 10) / 5

t_{(s)} = 4s.