__Cutting Force Calculator:__

__Cutting Force Calculator:__

Enter the values of material strength, σ_{(Pa), }cross sectional area of the material, A_{(m2)} in square metres, cutting zone coefficient, Z, efficiency of cutting process, E and tool factor, T to determine the value of cutting force, F_{t(N)}.

__Cutting Force Formula:__

__Cutting Force Formula:__

Cutting force is the force required to cut through a material using a tool or machine. This force is crucial in the manufacturing and materials processing industries, as it influences the selection of cutting tools, the power requirements of machines, and the quality of the finished product.

Cutting force, F_{t(N)} in Newton metres is calculated by the product of material strength, σ_{(Pa)}

in Pascals, cross sectional area of the material, A_{(m2)} in metre square, cutting zone coefficient, Z, efficiency of cutting process, E and tool factor, T.

Cutting force, F_{t(N)} = σ_{(Pa) }* A_{(m2)} * Z * E * T

F_{t(N)} = cutting force in Newton, N.

σ_{(Pa) }= material strength in Pascals, Pa.

A_{(m2)} = cross sectional area of the material in metre, m.

Z = cutting zone coefficient.

E = efficiency of cutting process.

T = tool factor.

__Cutting Force Calculation:__

1. Calculate the cutting force required to shear a steel plate with a yield strength of 250 MPa. The plate has a thickness of 5 mm and is being cut along a line that is 0.1 m long. Assume a cutting zone coefficient (Z) of 1.2, an efficiency (E) of 0.9, and a tool factor (T) of 1.1.

Given: σ_{(Pa) }= 250 * 10^{6} N/m^{2 }(converted from MPa to Pa), A_{(m2)} = 5 * 10^{-4} m^{2}, Z = 1.2, E = 0.9, T = 1.1

Cutting force, F_{t(N)} = σ_{(Pa) }* A_{(m2)} * Z * E * T

F_{t(N)} = 250 * 10^{6} * 5 * 10^{-4} * 1.2 * 0.9 * 1.1

F_{t(N)} = 165,000N.

2. A machining operation applies a cutting force of 1500 N. The material strength is 500 MPa (which is 500×10^{6} N/m² for conversion to SI units), the cutting zone coefficient is 1.2, the efficiency is 0.85, and the tool factor is 0.9. Calculate the cross-sectional area of the material being cut.

Given: σ_{(Pa) }= 500 * 10^{6} N/m^{2 }(converted from MPa to Pa), Z = 1.2, E = 0.85, T = 0.9, F_{t(N)} = 1500N.

Cutting force, F_{t(N)} = σ_{(Pa) }* A_{(m2)} * Z * E * T

A_{(m2)} = F_{t(N) }/ σ_{(Pa) }* Z * E * T

A_{(m2)} = 1500 / 500 * 10^{6} * 1.2 * 0.85 * 0.9

A_{(m2)} = 2.94 * 10^{-6} m^{2}.