__Bronze Square Angle Weight Calculator:__

__Bronze Square Angle Weight Calculator:__

Enter the vales of width, W_{(cm)}, thickness of the tube, T_{(cm)} and Length, L_{(cm)} to determine the value of Weight, W_{(g)}.

__Bronze Square Angle Weight Calculation: __

__Bronze Square Angle Weight Calculation:__

A bronze square angle is an L-shaped piece of metal with equal-length legs forming a right angle, used in various structural applications due to its strength and rigidity.

The weight of a bronze square angle is determined by its geometric dimensions specifically, the width of the legs, the thickness of the material, and the length of the angle as well as the density of the bronze alloy, which is typically around 8.4 to 8.6 g/cm^{3}.

In practical terms, the weight of a bronze square angle affects how it performs under loads, with heavier angles providing more resistance to bending and deformation due to increased mass and material distribution.

Bronze’s high density and inherent resistance to corrosion make it ideal for environments where structural integrity and longevity are important.

Weight, W_{(g)} in grams equals the difference between the square of width, W_{(cm)} in centimetres and the square of the difference between width, W_{(cm)} and thickness of the tube, T_{(cm)} in centimetres then divided by 2 and multiplied by Length, L_{(cm)} in centimetres and density of the bronze material, d_{(g/cm3)} in grams per cubic centimetre.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

W_{(g)} = weight in grams, g.

W_{(cm)} = width in centimetres, cm.

T_{(cm)} = thickness in centimetres, cm.

L_{(cm)} = length in centimetres, cm.

d_{(g/cm3)} = density in grams per cubic centimetres, g/cm^{3}.

__Bronze Square Angle Weight Calculation:__

- A bronze square angle has a width of 4 cm, a thickness of 0.5 cm, a length of 150 cm, and the density of bronze is 8.4 g/cm
^{3}. Calculate the weight of the angle.

Given: W_{(cm)} = 4cm, T_{(cm)} = 0.5cm, L_{(cm)} = 150cm, d_{(g/cm3)} = 8.4g/cm^{3}.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

W_{(g)} = ([4^{2} – (4 – 0.5)^{2}] / 2 ) * 150 * 8.4

W_{(g)} = (3.75 / 2) * 150 * 8.4

W_{(g)} = 1.875 * 150 * 8.4

W_{(g)} = 2362.5g.

- A bronze square angle weighs 1500 g, has a width of 3 cm, a thickness of 0.4 cm, and the density of bronze is 8.6 g/cm
^{3}. Find the length of the angle.

Given: W_{(cm)} = 3cm, T_{(cm)} = 0.4cm, W_{(g)} = 1500g, d_{(g/cm3)} = 8.6g/cm^{3}.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

L_{(cm)} = W_{(g)} / ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * d_{(g/cm3)}

L_{(cm)} = 1500 / ([3^{2 }– (3 – 0.4)^{2}]) * 8.6

L_{(cm)} = 1500 / 1.12 * 8.6

L_{(cm)} = 155.75cm.