__Brass Round Hollow Tube Weight:__

__Brass Round Hollow Tube Weight:__

Enter the values of outer radii, R_{(cm)}, inner radii, r_{(cm)} and tube’s length, L_{(cm)} to determine the value of weight of an brass round hollow tube, W_{(g)}.

__Brass Round Hollow Tube Weight:__

__Brass Round Hollow Tube Weight:__

A brass tube is characterized by its circular cross-section with a hollow centre, optimizing the use of material while maintaining structural integrity. The outer radius defines the external size of the tube, while the inner radius accounts for the hollow space inside.

The density of brass, a copper-zinc alloy known for its strength, resistance to corrosion, and aesthetic appeal, plays a crucial role in calculating the tube’s weight. The tube’s weight is a measure of how much material is present, influenced by the difference between the volume defined by the outer radius and the inner radius.

Mathematically, this is expressed by subtracting the inner cross-sectional area from the outer cross-sectional area, then multiplying the resulting area by the tube’s length and the density of brass.

This relationship shows that the greater the difference between the outer and inner radii, the heavier the tube will be, assuming the length and density remain constant.

The weight of an brass round hollow tube, W_{(g)} in grams is calculated by multiplying the difference between the squares of the outer radii, R_{(cm)} in centimetres and inner radii, r_{(cm)} in centimetres by pi, then multiplying by the tube’s length, L_{(cm)} in centimetres and finally by the material’s density, d_{(g/cm3)} in grams per cubic centimetres.

Weight of an brass round hollow tube, W_{(g)} = 3.14 * (R^{2}_{(cm)} – r^{2}_{(cm)}) * L_{(cm) }* d_{(g/cm3)}

W_{(g)} = weight of an brass round hollow tube in grams, g.

R_{(cm)} = outer radii in centimetres, cm.

r_{(cm)} = inner radii in centimetres, cm.

L_{(cm) }= length in centimetres, cm.

d_{(g/cm3)} = density in grams per cubic centimetres, g/cm^{3}.

__Brass Round Hollow Tube Weight Calculation:__

__Brass Round Hollow Tube Weight Calculation:__

- A brass round hollow tube has an outer radius 3 cm, an inner radius 2 cm, a length 100cm, and the density of brass is 8.5 g/cm
^{3}. Calculate the weight of the tube.

Given: R_{(cm)} = 3cm, r_{(cm)} = 2cm, L_{(cm) }= 100cm, d_{(g/cm3)} = 8.5g/cm^{3}.

Weight of an brass round hollow tube, W_{(g)} = 3.14 * (R^{2}_{(cm)} – r^{2}_{(cm)}) * L_{(cm) }* d_{(g/cm3)}

W_{(g)} = 3.14 * (3^{2} – 2^{2}) * 100 * 8.5

W_{(g)} = 3.14 * 5 * 100 * 8.5

W_{(g)} = 13345g.

- A brass round hollow tube has an outer radius 5 cm, an inner radius 3 cm and a density 8.5 g/cm
^{3}. The tube weighs 20000 g. Find the length of the tube.

Given: R_{(cm)} = 5cm, r_{(cm)} = 3cm, W_{(g)} = 20000g, d_{(g/cm3)} = 8.5 g/cm^{3}.

Weight of an brass round hollow tube, W_{(g)} = 3.14 * (R^{2}_{(cm)} – r^{2}_{(cm)}) * L_{(cm) }* d_{(g/cm3)}

L_{(cm) }= W_{(g)} / 3.14 * (R^{2}_{(cm)} – r^{2}_{(cm)}) * d_{(g/cm3)}

L_{(cm) }= 20000 / 3.14 * (5^{2} – 3^{2}) * 8.5

L_{(cm) }= 46.99cm.