__Aluminium Square Angle Weight Calculator:__

__Aluminium Square Angle Weight Calculator:__

Enter the values of width, W_{(cm)}, thickness of the tube, T_{(cm)} and Length, L_{(cm)} to determine the value of Weight, W_{(g)}.

__Aluminium Square Angle Weight Formula:__

__Aluminium Square Angle Weight Formula:__

The physics of aluminium square angle weight revolves around the principles of material density and geometric volume calculation. An aluminium square angle is an “L”-shaped structural component with two perpendicular legs forming a right angle.

The weight of such an angle depends on its geometric dimensions and the density of the aluminium material.

Aluminium’s density is crucial as it determines how much mass is contained within a given volume. The angle’s weight is calculated by first determining the cross-sectional area of the angle, which is obtained by subtracting the area of the inner part from the outer part of the angle. This area calculation accounts for the hollow nature of the angle, with the material’s thickness creating a difference between the outer and inner sections.

Weight, W_{(g)} in grams equals the difference between the square of width, W_{(cm)} in centimetres and the square of the difference between width, W_{(cm)} and thickness of the tube, T_{(cm)} in centimetres then divided by 2 and multiplied by Length, L_{(cm)} in centimetres and density of the aluminium material, d_{(g/cm3)} in grams per cubic centimetre.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

W_{(g)} = weight in grams, g.

W_{(cm)} = width in centimetres, cm.

T_{(cm)} = thickness in centimetres, cm.

L_{(cm)} = length in centimetres, cm.

d_{(g/cm3)} = density in grams per cubic centimetres, g/cm^{3}.

__Aluminium Square Angle Weight Calculation:__

__Aluminium Square Angle Weight Calculation:__

- Calculate the weight of an aluminium square angle with a leg width of 4 cm, thickness of 0.5 cm, length of 100 cm, and density of 2.7 g/cm
^{3}:

Given: W_{(cm)} = 4cm, T_{(cm)} = 0.5cm, L_{(cm)} = 100cm, d_{(g/cm3)} = 2.7g/cm^{3}.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

W_{(g)} = ([4^{2} – (4 – 0.5)^{2}] / 2 ) * 100 * 2.7

W_{(g)} = (3.75 / 2) * 100 * 2.7

W_{(g)} = 1.875 * 100 * 2.7

W_{(g)} = 506.25g.

- Find the length of an aluminium square angle if the width is 6 cm, thickness is 1 cm, density is 2.8 g/cm³, and the total weight is 840 grams:

Given: W_{(cm)} = 6cm, T_{(cm)} = 1cm, W_{(g)} = 840g, d_{(g/cm3)} = 2.8g/cm^{3}.

Weight, W_{(g)} = ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * L_{(cm)} * d_{(g/cm3)}

L_{(cm)} = W_{(g)} / ( [ W^{2}_{(cm)} – (W_{(cm) }– T_{(cm)})^{2} ] / 2 ) * d_{(g/cm3)}

L_{(cm)} = 840 / ([6^{2 }– (6 – 1)^{2}]) * 2.8

L_{(cm)} = 840 / 15.4

L_{(cm)} = 54.55cm.