### Wire Resistance Calculator:

This wire resistance calculator can quickly calculate the electrical properties of a particular wire – its resistance and conductivity.

For example, you will learn how to estimate the resistance of a wire using the resistance formula known as Pouillet’s Law.

One of the conductors is copper, which is found in almost every electrical device.

- Find out what is the conductivity of copper and the resistivity of copper and what units of resistivity and conductivity units to use.
- Below are simple steps to find wire conductance and resistance.
- Get the type of wire material, its length and area.
- Multiply the resistance of the object by its length.
- Divide the product by the area of the wire to get its resistance.
- Find the resonance of the resistance to check the wire conductance value.

Wire resistance is defined as the property of a wire that resists the flow of current.

Resistivity is nothing but the resistance offered by a material per unit length per unit cross-sectional area. The higher the resistance of the material, the more difficult it is for current to flow.

Electrical conductivity is defined as the amount of voltage required to allow electricity to flow.

### Wire Resistance Formula:

Wire Resistance R_{(oh)} in ohms is equal to the resistivity of the material ρ _{(Ωm)} in ohms per meter and multiply the wire length L_{(m)} in meter and divided by cross – sectional area of the wire A_{(m2)} in meter^{2}.Hence the Wire Resistance formula can be written as

R_{(oh)} =ρ _{(Ωm)} *L_{(m)} /A_{(m2)}

G =σ A /L

R = 1/G

Where

R = is the Resistance

σ =is the conductivity

ρ = is the resistivity of the material

L= is the wire length

A= is the cross – sectional area of the wire

G= is the conductance

### Example:1

Calculate the resistance and conductance of the material whose resistivity is 4.5Ωm and conductivity is 0.48 s/m.The aluminium wire length is 20m and cross sectional area is 4m^{2}?

### Answer:

Given that

Resistivity of the wire ρ =4.5Ωm

Conductivity of the wire σ = 0.48 s /m

Wire length L =20m

Cross – sectional area A = 4m^{2}

Resistance of the material R =ρ*L /A

R =(4.5 * 20 ) / 4

R=90 / 4

R =22.5Ω

Conductance G =1/R

=1/ 22.5

=0.0444 s

Therefore, the resistance and conductance of the wire is 22.5Ω and 0.0444 s

### Example:2

Calculate the resistivity 0.0000000244 and length 95 m and Area 60m^{2}.Find the Resistance value?

### Answer:

Resistivity ρ =0.0000000244

Length =95m

Area =60 m^{2}

Resistance = ρ *L /A

=0.0000000244 *95 / 60

=0.00000038633 Ω