### Thermal Expansion Calculator:

Every substance is made up of molecules, More or less densely packed together. When we increase the temperature of matter, we are actually imparting energy. Obviously, the energy cannot disappear; It converts its form into kinetic energy. As the molecules have more kinetic energy, they start moving more.

You can imagine that the more they move, the farther they have to stay. As the separation between molecules increases, the material expands.

The idea behind this thermal expansion calculator is simple: when you heat a material, it expands. If you cool it, it shrinks. How much though? Well, it depends on a property of the material called “coefficient of thermal expansion”. In this article, we explain this concept in more detail.

### Thermal Expansion Formula:

Thermal expansion equation is linear expansion ΔL_{(m)} in meter is equal to the linear expansion coefficient a_{(k)} in Kelvin and multiply the initial length L_{1(m)} in meter and multiply the final temperature T_{2} _{(0c)} in degree Celsius and minus the initial temperature T_{1(0c)} in degree Celsius .Hence the linear expansion formula can be written as

Linear expansion ΔL_{(m)}=a_{(k)}*L_{1(m)}(T_{2} _{(0c)} -T_{1}_{(0c)})

Volumetric expansion Δv=b *v_{1}(T_{2}-T_{1})

T_{1}=is the initial temperature in ^{}c

T_{2}=is the final temperature in ^{}c

ΔL=is the change in object’s length in meter

L_{1}=is the initial length in meter

A=is the linear expansion coefficient in kelvin

Δv=is the change in object’s volume

V_{1}=is the initial volume and

B=is the volumetric expansion coefficient

### Example:1

Calculate the initial length 100m and final length 200m and initial temperature 80^{}c and final temperature 100^{}c.Find linear expansion value?

### Answer:

T_{1}=80^{}c

T_{2}=100^{}c

L_{1}=100m

L_{2}=200m

By using formula

ΔL(L_{2}-L_{1})=is the change in object’s length

a= ΔL_{(m)}/L_{1(m)}(T_{2} _{(0c)} -T_{1(0c)})

a=0.051 k

### Example:2

Calculate the initial volume 45 m^{3}, finial volume 200m^{3} and initial temperature 50^{}c and final temperature 100^{}c.Find the volumetric expansion value?

### Answer:

T_{1}=50^{}c

T_{2}=100^{}c

v_{1}=45 m^{3}

v_{3}=200m^{3}

By using formula

Δv(L_{2}-L_{1})=is the change in object’s length

b= Δv_{(m3)}/v_{1(m)}(T_{2} _{(0c)} -T_{1(0c)})

a=0.068888888888888891/ k