### Specific Heat Calculator:

In physics, specific heat is an important thermodynamic property.

It is defined as the amount of heat per unit mass required to raise the temperature by one degree Celsius. The specific heat value can have a different range for different materials depending on the extent to which the material absorbs heat. The SI unit of specific heat is joule per kelvin and kilogram (J/K kg).

Specific heat is defined as the amount of heat per unit mass required to raise the temperature by one degree Celsius. The specific heat for different materials varies from one another and depends on the extent to which they absorb heat.

Follow the simple steps given below to calculate specific heat. They are as follows

First, determine the initial and final temperatures, the mass of the sample, the amount of energy or heat supplied.

Find the difference between the initial and final temperatures to obtain the change in temperature (ΔT).

Then, find the product of the change in temperature and the mass of the sample.

To get the specific heat or heat capacity, divide the heat or energy supplied by the product obtained in the previous step.

To change the unit, just long press the unit selection.

### Specific Heat Formula:

Specific heat formula c_{(j/kg-k)} in joule per kilogram per kelvin is equal to the amount of heat supplied Q_{(j)} in joule and divied by the mass m_{(g)} in gram and multiply the difference between the initial and final temperature ΔT_{(0c)} in degree Celsius .Hence the specific heat formula can be written as

Heat capacity formula is given by

c_{(j/kg-k)}=Q_{(j)}/(m_{(g)}*ΔT_{(0c)})

Where Q is the amount of heat supplied in joules

M=is the mass of the sample

ΔT=is the difference between initial and final temperatures

Units of specific Heat are j/(kg-k) or j/kg c

### Example:1

If you have 15g of piece of metal that absorbs 150j of heat while increasing from 45^{}c to 55^{}c.How will you find its specific heat?

### Answer:

Given that

Energy =150j

Initial temperature =45^{}c

Final temperature= 55^{}c

Mass of metal =15g

Change in temperature ΔT= 45^{}c to 55^{}c=10^{}c

We know the formula to calculate specific heat or heat capacity c=Q/(m* ΔT)

Substituting the inputs we have the equation for heat capacity as under

C= Q/(m* ΔT)

C=150j/15g*10^{}c

C=100j/(kg.k)

### Example:2

If you have 25g of piece of metal that absorbs 200j of heat while increasing from 28^{}c to 35^{}c.How will you find its specific heat?

### Answer:

Given that

Energy =200j

Initial temperature =28^{}c

Final temperature= 35^{}c

Mass of metal =25g

Change in temperature ΔT= 28^{}c to 35^{}c=7^{}c

We know the formula to calculate specific heat or heat capacity c=Q/(m* ΔT)

Substituting the inputs we have the equation for heat capacity as under

C= Q/(m* ΔT)

C=200j/25g*7^{}c

C=56j/(kg.k)