# Series Resistor Calculator, Formula, Resistance Calculation With Example

### Series Resistor Calculator:

A series resistance calculator is a tool for determining the equivalent resistance of a circuit consisting of ten resistors connected in series. Read or go to Parallel Resistance Calculator.

It gives instant results and provides detailed explanation to solve it. Read more sections to know steps to find equivalent resistance of series resistors and solved questions.

• Find the resistance of all resistors connected in series.
• Add those resistances to get the total resistance.
• A resistor is a device used to control or limit the flow of current in an electrical circuit.

Its SI unit is Ohm. These resistors can be connected in series or parallel in a circuit. If resistors are connected in series, a common current flows through them all.

Hence, the total resistance becomes the sum of the individual resistances.

Check out the step-by-step procedure to help calculate equivalent resistance in series circuits. Follow these steps to get the result effortlessly

### Resistors in Series Formula:

Resistors in series formula is the equivalent series resistance R(oh) in ohms is equal to the R1 , R2 , R3…… Rn are the resistances of individual resistors R1(oh) + R2(oh) + R3(oh)+………Rn(oh)  in ohms.Hence the Resistors in series formula can be written as

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R(oh)= R1(oh) + R2(oh) + R3(oh)+………Rn(oh)

Where

R= is the equivalent series resistance

R1 , R2 , R3…… Rn are the resistances of individual resistors

### Example:1

If 4 resistors are connected in series and their resistances are 8 Ω , 16 Ω, 25 Ω,35 Ω.Find the total resistance in the circuit?

Given that

First resistor resistance R1 =8 Ω

Second Resistance  R2  = 16 Ω

Third Resistance R3 = 25 Ω

Fourth Resistance R4 =35 Ω

Equivalent series resistance R = R1 +R2 +R3 + R4

R= 4+10+15+22

=51 Ω

Therefore, equivalent series resistance is 51 Ω

### Example:2

If 2  resistors are connected in series and their resistances are 90 Ω , 150 Ω.Find the total resistance in the circuit?

Given that

First resistor resistance R1 =90 Ω

Second Resistance  R2  = 150 Ω

Equivalent series resistance R = R1 +R2

R= 90+150

=240 Ω

Therefore, equivalent series resistance is 240 Ω